0=15p^2+80p+80

Solution for 0=15p^2+80p+80 equation:

0=15p^2+80p+80

We move all terms to the left:

0-(15p^2+80p+80)=0

We add all the numbers together, and all the variables

-(15p^2+80p+80)=0

We get rid of parentheses

-15p^2-80p-80=0

a = -15; b = -80; c = -80;
Δ = b2-4ac
Δ = -802-4·(-15)·(-80)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-40}{2*-15}=\frac{40}{-30}
=-1+1/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+40}{2*-15}=\frac{120}{-30}
=-4
$